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4n^2-40n+64=0
a = 4; b = -40; c = +64;
Δ = b2-4ac
Δ = -402-4·4·64
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-24}{2*4}=\frac{16}{8} =2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+24}{2*4}=\frac{64}{8} =8 $
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